Tính toán, lập trình thiết kế động cơ không đồng bộ một pha

%c",196);gotoxy(i,23); printf("%c",196);} gotoxy(77,1);printf("%c",191);gotoxy(77,23);printf("%c",217); gotoxy(1,23); printf("%c",192); for( i=2;i<23;i++){gotoxy(1,i); printf("%c",179); gotoxy(77,i);printf("%c",179);} textcolor(13); gotoxy(22,2); cprintf("TRUONG DAI HOC BACH KHOA HA NOI "); gotoxy(30,3); cprintf("KHOA DIEN"); gotoxy(23,4); cprintf("BO MON THIET BI DIEN- DIEN TU "); gotoxy(28,7); cprintf("DO AN TOT NGHIEP "); gotoxy(10,10); cprintf(" CHUONG TRINH THET KE DONG CO KDB MOT PHA DIEN DUNG"); gotoxy(45,15); cprintf("GVHD : TS NGUYEN HONG THANH"); gotoxy(45,17); cprintf("SVTH : NGUYEN HUU XUYEN"); getch();} float Pdm,hs,p,cosphi,mmax,mk,ik,Udm; void nhap(){ char chon; cout<<"Ban muon nhap du lieu dau vao khong(c hoac k) chon="; cin>>chon;if(chon=='k'){ Pdm=180; hs=0.55; cosphi=0.74; mmax=1.7; Udm=220; mk=0.5;ik=1.5; p=1;} else{ cprintf(" Nhap cong suat dinh muc Pdm="); cin>>Pdm; cprintf(" Nhap dien ap dinh muc Udm="); cin>>Udm; do { cout>hs; if((hs>100)| (hs<0)) cout<<"\nBan nhap sai hay nhap hieu suat nho hon 1 lon hon 0";} while((hs>100)||(hs<0));hs=hs/100; do { cout>cosphi; if((hs>100)||(hs<0)) cout<<"\nBan da nhap sai hay nhap he so cong suot nho hon 1 lon hon 0"; } while((cosphi>100)||(cosphi<0)); cosphi=cosphi/100; cout>mmax; cout>mk; cout>ik; cout>p;} getch();} void main(){ nhap();} 3> M« ®un x¸c ®Þnh kÝch th­íc c¬ b¶n vµ th«ng sè pha chÝnh. #include #include #include #include #include #include #include float lda,Pdm3,Idm,Qa,Qb,Zs,Zr,Za,Zb,Kd,Bkk,A,Att,D,Dn,l, khkk,phi,ke,kett,Ssa,kda,Wsa,Ura,d,dcd,bt1; void ktcoban(){ cout<<"Ban muon chon cac he so de tinh kich thuoc co ban khong(chon c hoac k) ch="; char ch;float tg1,tg2,saiso,Ps3,lapA=0; cin>>ch;if(ch=='k'){ bt1=1.5; Pdm3=bt1*Pdm; Ps3=Pdm3/tra_hscos3(Pdm3,p); Kd=0.55; //cout<<"tra_hscos3(Pdm3,p)="<<tra_hscos3(Pdm3,p); lda=0.9; A=115; Bkk=0.5; Dn=44*pow((Ps3*p*p/(Bkk*A*lda*3000)),0.333333)/Kd; //cong thuc tinh duong kinh ngoai cout<<"Khi chua quy chuan Dn="<<Dn<<"(cm)"; Dn=QchuanDn(Dn);//quy chuan dk ngoai theo bang trang 26 cout<<" sau khi quy chuan Dn="<<Dn<<"(cm)"; D=Kd*Dn;//duong kinh trong to=3.14*D/(2*p);//buoc cuc l=lda*D; printf("\nDK trong stato D=%0.2f chieu dai stato l=%0.2f",D,l); Zs=24;Zr=19; Za=Zs/2; Zb=Zs/2; Qa=Za/(2*p); Qb=Zb/(2*p); cout<<"\nSo ranh pha A va B Za="<<Za<<" Zb="<<Zb; cout<<" Qa="<<Qa<<" Qb="<<Qb; kda=0.707/(Qa*sin(45/Qa));//he so day quan printf("\nHe so day quan Kdq=%0.3f",kda); Idm =Pdm/(hs*cosphi*1.414*Udm); cout<<"\nDong dien dinh muc Idm="<<Idm<<"(A)"; phi=0.000066*to*l*Bkk;//cong thuc tinh tu thong cout<<" tu thong phi="<<phi<<"(Wb)"; ke=0.82; Wsa=ke*Udm/(220*phi*kda); Ura=1*Wsa/(p*Qa); cout<<"\nKhi chua lam tron :Wsa="<<Wsa<<" Ura="<<Ura; tg1=fabs(Ura-floor(Ura)); tg2=fabs(Ura-ceil(Ura));//lam tron thanh so nguyen duong if(tg1>=tg2) Ura=ceil(Ura);//lam tron thanh so nguyen duong else Ura=floor(Ura); Ura=Ura; Wsa=Ura*p*Qa; ke=Wsa*220*phi*kda/Udm; khkk=0.3; cout<<"\nSau khi lam tron :Wsa="<<Wsa<<" Ura="<<Ura; else { do{ cout<<"Chon he so beta1( chon beta1=1.25-1.7) bt1="; cin>>bt1;} while((bt1>1.7)||(bt1<1.25)); Pdm3=bt1*Pdm; Ps3=Pdm3/tra_hscos3(Pdm3,p); cout<<"\ncong suat Pdm3="<<Pdm3<<" vaPs3="<<Ps3; do{ cout<<"\nChon he so lamda ( chon lamda=0.22-1.57) lda="; cin>>lda;} while((lda>1.57)||(lda<0.22)); //Chon Kd if(p==1)do { cout<<"Chon Kd (Ban chi chon Kd=0.485-0.615) Kd="; cin>>Kd;} while((Kd>0.615)||(Kd<0.485)); if(p==2)do{ cout<<"Chon Kd ( chon Kd=0.495-0.655) Kd="; cin>>Kd;} while((Kd>0.655)||(Kd<0.495)); do{ cout<<"Chon Bkk=0.3-1(T)) Bkk="; cin>>Bkk;} while((Bkk>1)||(Bkk<0.3)); //Chon tai duong A do{ cout>khkk; if((khkk0.31)) cout<<"\nBan da chon sai ,hay chon lai trong khoang";} while((khkk>0.31)||(khkk<0.2)); do{ if(p==1) do{ cout<<"Chon tai duong A (Ban chon A=90-180(A/cm)) A="; cin>>A;} while((A>180)||(A<90)); if(p==2) do{ cout<<"Chon tai duong A (Ban chon A=90-200(A/cm))A="; cin>>A;} while((A>200)||(A<90)); Dn=44*pow((Ps3*p*p/(Bkk*A*lda*3000)),0.333333)/Kd; // cong thuc tinh duong kinh ngoai cout<<"Khi chua quy chuan Dn="<<Dn<<"(cm)"; Dn=QchuanDn(Dn);//quy chuan dk ngoai theo bang trang 26 cout<<" sau khi quy chuan Dn="<<Dn<<"(cm)"; D=Kd*Dn;//duong kinh trong to=3.14*D/(2*p);//buoc cuc l=lda*D; //chieu dai stato cout<<"Ban hay chon so rang ranh stato,roto Zs/Zr:"; //theo bang Zs/Zr trang 28"; cin>>Zs;cout>Zr; Za=Zs/2;Zb=Zs/2; Qa=Za/(2*p); Qb=Zb/(2*p); cout<<"\ n So ranh pha A va B Za="<<Za<<" Zb="<<Zb; cout<<" Qa="<<Qa<<" Qb="<<Qb; kda=0.707/(Qa*sin(45/Qa));//he so day quan cout <<"\n He so day quan Kdq="<<kda; Idm =Pdm/(hs*cosphi*1.414*Udm); cout<<"\ndong dien dinh muc Idm="<<Idm<<"(A)"; phi=0.000066*to*l*Bkk; cout<<"\nTu thong phi="<<phi<<"(Wb)"; do{ cout<<"\nGia tri ke nam trong khoang : 0.7-0.9";{ cout>ke; if((ke>0.9)||(ke<0.7)) cout<<"\nBan da chon sai ,hay chon lai ";} while((ke>0.9)||(ke<0.7)); Wsa=ke*Udm/(220*phi*kda); cout<<"\nSo vong day pha A :Wsa="<<Wsa; Ura=1*Wsa/(p*Qa); cout<<" Ura="<<Ura; tg1=fabs(Ura-floor(Ura));tg2=fabs(Ura-ceil(Ura)); if(tg1>=tg2) Ura=ceil(Ura); else Ura=floor(Ura); Wsa=Ura*p*Qa; ke=Wsa*220*phi*kda/Udm; cout<<"\nSau khi lam tron :Wsa="<<Wsa <<" Ura="<<Ura<<" va ke ="<<ke;} while((ke>0.9)||(ke<0.7)); Att=2*Wsa*Idm/(3.14.D); cout<<"\ntai duong tinh toan Att="<<Att; saiso=fabs(Att-A)*100/Att; cout<<"\nsai so= "<<saiso; if(saiso>15) {lapA++;if(lapA>6) { cout<<"\nBan phai thoat ra ngoai de chon lai ";getch();exit(1);}}} while(saiso>15);} A=Att; Ssa=Idm/6; cout<<"\nTiet dien day dan khi chua quy chuan Ssa="<<Ssa; Ssa=tra_tiet_dien(Ssa); cout<<" sau khi quy chuan Ssa="<<Ssa; d=Tra_dkocd(Ssa); dcd=Tra_dk_cd(Ssa); cout<<"\nDuong kinh day tran d="<<d<<" va day co cach dien dcd="<<dcd; getch();} void main(){ nhap(); ktcoban(); getch();} 4>M« dun x¸c ®Þnh kÝch th­íc r¨ng,r·nh stato #include #include #include #include #include #include #include #include void tustato(){ float Kldmax,Kldmin,Bzsmin=1.2,Bzsmax=1.6,Bgsmin=0.9,Bgsmax=1.3, Fsmin,bzsmin,bzsmax,hgsmax,hgsmin,Srsmax,Srsmin,Fgs,Fzs,Fts,xigs; if(p==1) {Kldmin=0.7,Kldmax=0.75;} if(p==2) {Kldmin=0.69,Kldmax=0.75;} D=D*10; //nhan 10de quy doi sang mm ts=pi*D/Zs; Dn=10*Dn; cout>b4s; printf("Kldmin=%0.2f Kldmax=%0.2f",Kldmin,Kldmax); Srsmin=Ura*dcd*dcd/(0.9*Kldmax); Srsmax=Ura*dcd*dcd/(0.9*Kldmin); printf("\ntiet dien so bo cua ranh:Srmin=%0.4f Srmax=%0.4f",Srsmin,Srsmax); hgsmin=10*phi*10000/(2*l*Bgsmax*kc); hgsmax=10*phi*10000/(2*l*Bgsmin*kc); printf("\n hgsmin= %0.4f",hgsmin); printf(" hgsmax= %0.4f",hgsmax); printf(" ts=%8.5f",ts); bzsmin=Bkk*ts/(kc*Bzsmax); bzsmax=Bkk*ts/(kc*Bzsmin); if(bzsmin<1.8) bzsmin=1.8; printf("\nbzsmin=%0.4f",bzsmin); printf(" bzsmax=%0.4f",bzsmax); int m,n,k=0,li,lj; float delta_bzs,delta_hgs; printf("\n So lan chia bzs n=");cin>>n; printf(" So lan chia hgs m=");cin>>m; delta_bzs=(bzsmax-bzsmin)/n; delta_hgs=(hgsmax-hgsmin)/m; getch(); for(int i=0;i<=n;i++) { bzs=bzsmin+delta_bzs*i; d1s=(3.14*(D+2*h4s)-(bzs*Zs))/(Zs-3.14); for(int j=0;j<=m;j++){ hgs=hgsmin+j*delta_hgs; d2s=(3.14*(Dn-2*hgs)-bzs*Zs)/(Zs+3.14); hrs=(Dn-D-2*hgs)/2; h12s=hrs-0.5*(d1s+d2s-2*h4s); Srs=3.14*d1s*d1s/8+3.14*d2s*d2s/8+h12s*0.5*(d1s+d2s); if(h12s>0)if(Srs>=Srsmin)if(Srs<=Srsmax){ Bzs=Bkk*ts/(bzs*kc);Hzs=traH_Bz(Bzs); hzs=hrs-0.1*d1s;Fzs=hzs*Hzs/10; Bgs=phi*10000/(2*(hgs/10)*l*kc); Hgs=traH_Bg(Bgs); xigs=traxi_Bg(Bgs); Fgs=xigs*Hgs*pi*(Dn-hgs)/(2*p); k=k+1; Fts=Fzs+Fgs; if(k==1) Fsmin=Fts; else if(Fsmin>=Fts) { Fsmin=Fts;li=i;lj=j;}}}} cout<<"\nli="<<li<<" lj="<<lj; if((lin)) { cout<<"\nKhong toi uu duoc thoat ra chon lai kich thuoc co ban"; getch();exit(1);} else{ printf("\nFsmin===%0.5f",Fsmin); bzs=bzsmin+delta_bzs*li; printf(" bzs=%0.2f",bzs); d1s=(3.14*(D+2*h4s)-(bzs*Zs))/(Zs-3.14); printf(" d1s=%0.2f",d1s); hgs=hgsmin+lj*delta_hgs; printf("\nhgs=%0.2f",hgs); d2s=(3.14*(Dn-2*hgs)-bzs*Zs)/(Zs+3.14); printf(" d2s=%0.2f",d2s); hrs=(Dn-D-2*hgs)/2; printf(" hrs=%0.2f",hrs); h12s=hrs-0.5*(d1s+d2s+2*h4s); printf(" h12s=%0.2f",h12s); Srs=3.14*(d1s*d1s+d2s*d2s)/8+h12s*0.5*(d1s+d2s); Kld=Ura*dcd*dcd/(0.9*Srs); printf("\n Kld=%0.3f",Kld); hzs=hrs-0.1*d1s; printf(" hzs=%0.2f",hzs); printf(" Srs=%0.4f",Srs); Bzs=Bkk*ts/(kc*bzs); printf(" Bzs==%0.4f",Bzs); Bgs=10*phi/(2*l*hgs*kc)*10000; printf(" Bgs==%0.4f",Bgs);}} void main(){ clrscr(); nhap(); ktcoban(); tustato(); getch();} 5>X¸c ®Þnh kÝch th­íc r¨ng,r·nh roto #include #include #include #include #include #include #include #include #include #include char vlieu; float hgr,hrr,h12r,Bgr,bzr,Bzr,hzr,Sr,Jtd,Jv,Sv,Iv,Itd, d1r,d2r,Fr,dt,av,bv,Dv,h4r,b4r,Dr,tr; void turoto(){ int i,j,i1,j1,j2,K,K1; float Bgrmax=1.5,Bgrmin=0.8,Bzrmin=1,Bzrmax=1.8, Srmax,Srmin,Srr,Jmin,Jmax, delta_Bzr,delta_Bgr,Hzr,Hgr,xigr,Fzr,Fgr,Fmin,Frr; Itd=tra_k1(cosphi)*Idm*4*Wsa*kda/Zr; cout<<"\nDong dien trong thanh dan roto Itd="<<Itd<<"(A)"; cout<<"\nBan chon thanh dan bang dong (go d) hay nhom (go n) vlieu="; cin>>vlieu; Dr=(D-2*khkk); tr=3.14*Dr/Zr; cout<<" buoc rang roto tr="<<tr<<" cm"; h4r=0.3; cout<<" mieng ranh roto lay bang b4r=1.5";b4r=1.5; if(vlieu=='d'){ Jmin=3.5;Jmax=5;} if(vlieu=='n') {Jmin=2;Jmax=3;} Srmin=Itd/Jmax; Srmax=Itd/Jmin; printf("\nDien tich ranh max Srmax=%0.3f va min Srmin=%0.3f",Srmax,Srmin); cout>K; cout>K1; delta_Bzr=(Bzrmax-Bzrmin)/K; delta_Bgr=(Bgrmax-Bgrmin)/K1; dt=0.3*D; getch(); j2=0; for(i=0;i<K+1;i++){ Bzr=Bzrmin+i*delta_Bzr; bzr=Bkk*tr/(Bzr*kc); if(bzr>=1.8){ d1r=((Dr-2*h4r)*pi-bzr*Zr)/(Zr+pi); for(j=0;j<K1+1;j++){ Bgr=Bgrmin+j*delta_Bgr; hgr=10*1e+4*phi/(2*Bgr*l*kc);//nhan 10 la do doi ra mm d2r=((dt+2*hgr)*pi-bzr*Zr)/(Zr-pi); if(d2r>=2.5){ h12r=0.5*(Dr-d1r-2*h4r-Zr*(bzr+d2r)/pi); hrr=h12r+h4r+0.5*(d1r+d2r); Srr=pi*(pow(d1r,2)+pow(d2r,2))/8+0.5*h12r*(d1r+d2r); if((Srr>=Srmin)&&(Srr<=Srmax)){ //Tinh suc tu dong rang roto Hzr=traH_Bz(Bzr); hzr=hrr-0.1*d1r; Fzr=2*hzr*Hzr/10;//chia 10 de doi sang cm //Tinh suc tu dong gong roto Hgr=traH_Bg(Bgr); xigr=traxi_Bg(Bgr); Fgr=xigr*Hgr*3.14*(dt+2*hgr)/(20*p); Frr=Fzr+Fgr; if(j2==0) Fmin=Frr;j2=1; if(Fmin>=Frr){ Fmin=Frr;i1=i;j1=j;}}}}}} cout<<"\ni1="<<i1<<" j1="<<j1; if((i1K)) { cout<<"khong toi uu duoc thoat ra ngoai"; getch(); exit(1);} cout<<" Kinh thuoc ranh roto la:";Bzr=Bzrmin+i1*delta_Bzr; printf("\n Bzr=%0.3f",Bzr);bzr=Bkk*tr/(Bzr*kc); printf("bzr=%0.2f",bzr);d1r=((Dr-2*h4r)*pi-bzr*Zr)/(Zr+pi); printf(" d1r=%0.2f",d1r);Bgr=Bgrmin+j1*delta_Bgr; printf(" Bgr=%0.3f",Bgr);hgr=10*1e+4*phi/(2*Bgr*l*kc); printf(" hgr=%0.2f",hgr);//tinh hgr nhan 10 la doi ra (mm) d2r=((dt+2*hgr)*pi-bzr*Zr)/(Zr-pi); printf(" d2r=%0.2f",d2r); h12r=0.5*(Dr-d1r-2*h4r-Zr*(bzr+d2r)/pi); printf(" h12r=%0.2f",h12r); hrr=h12r+h4r+0.5*(d1r+d2r); printf(" hrr=%0.2f",hrr); Sr=pi*(pow(d1r,2)+pow(d2r,2))/8+0.5*h12r*(d1r+d2r); printf("\nDien tinh ranh roto Sr=%0.3f",Sr); Jtd=Itd/Sr; printf(" mat do dong trong thanh dan Jtd=%0.3f",Jtd); hzr=hrr-0.1*d2r; Fr=Fmin;cout<<"\nSuc tu dong roto min Fr="<<Fr; bv=1.2*hrr;bv=ceil(bv); cout<<"\nBan hay chon mat do dong vanh ngan mach trong khoang " >Jv; Iv=Itd/(2*sin(pi*p/Zr)); Sv=Iv/Jv;av=Sv/bv;printf("\n Iv=%0.4f Sv=%0.4f",Iv,Sv); if(fabs(av-floor(av))>=fabs(av-ceil(av))) av=ceil(av); else av=floor(av); Dv=Dr-bv-2*khkk; cout<<"\nKich thuoc vanh ngan mach:av="<<av<<" bv="<<bv; printf(" Dv=%0.1f",Dv);} void main(){ clrscr(); nhap(); ktcoban(); tustato(); turoto(); getch();} 6>M« dun x¸c ®Þnh trë kh¸ng stato vµ roto 6.1 Trë kh¸ng stato #include #include #include #include #include #include #include #include #include #include float Xsa,Rsa,kdr,k_delta,k_delta_r,k_delta_s,Lsa,lamda_tong; void tinh_tro_khang_stato(){ float ld,ltb,lamda_r,lamda_t,lamda_d, bn,anpha_n,kn,bta_r ,eta,epxilon,phiB,b1s, delta_Zr,delta_Zs,k1,to_y,h1,h2,bta,bcd=0.2,hn=2; if(p==2) k1=1.3;if(p==1) k1=1.2; to_y=3.14*(D+2*hrs)/(2*p*10);//chia 10 de doi sang cm ld=k1*to_y+2; //chon he so B=1 ltb=l+ld; cout<<"\nchieu daibinh quan nua vong day:ltb="<<ltb<<"(cm)"; Lsa=0.02*ltb*Wsa; cout<<" tong chieu dai day dan mot pha Lsa="<<Lsa<<"(m)"; Rsa=0.0213*Lsa/(Ssa);//dien tro tac dung day quan stato cout<<"\nDien tro cua day stato:Rsa="<<Rsa<<"(om)"; cout<<"\n Vi day quan 1 lop buoc du k_bta1=1 k_bta=1"; h2=hn+bcd-d1s/2; h1=hrs-h4s-d1s/2-bcd-h2-0.1*d2s; lamda_r=h1/(3*d1s)*1+(0.875-b4s/(2*d1s)+h2/d1s+h4s/b4s)*1; cout<<"\n Buoc rang stato ts="<<ts<<" cm";bn=ts; cout<<"\nLam ranh nghieng o roto 1 buoc rang roto bn="<<bn; anpha_n=2*p*pi*bn/(Zs*tr); cout<<"\nanpha_n="<<anpha_n; kn=2*sin(anpha_n/2)/anpha_n; kdr=kn; cout<<"\nhe so ranh nghieng: kn=kdr="<<kdr; eta=Zs/Zr; epxilon=3.14*p*b4s/(Zs*ts); k_delta_s=(5+b4s/khkk)/(5+b4s*(ts-b4s)/(khkk*ts)); cout<<" \nk_delta_s="<<k_delta_s; k_delta_r=(5+b4r/khkk)/(5+b4r*(tr-b4r)/(khkk*tr)); cout<<" k_delta_r="<<k_delta_r; k_delta=k_delta_s*k_delta_r; cout<<" k_delta="<<k_delta; delta_Zs=k_delta_s-1-3*k_delta_s*b1s/(3.14*p*Zs); cout<<" delta_Zs="<<delta_Zs; lamda_t=ts/(11.9*khkk*k_delta_r); lamda_d=0.27*Qa/l*(ld-0.64*to); cout<<"\nCac he so tu tan cua stato:\nlamda_r="<<lamda_r<<" lamda_t=" <<lamda_t<<" lamda_d="<<lamda_d; lamda_tong=lamda_r+lamda_t+lamda_d; cout<<"\nTong hsotu tan stato:lamda_tong="<<lamda_tong; Xsa=(0.158*Wsa*Wsa*l*lamda_tong)/(10000*p*Qa); cout<<"\nDien khang tan day quan chinh stato:Xsa="<<Xsa<<"(Om)";} void main(){ clrscr(); nhap(); ktcoban(); tustato(); tinh_tro_khang_stato(); getch(); 6.2Trë kh¸ng roto #include #include #include #include #include #include #include #include #include #include #include #include float Rr,Xr,Xma,Fm,F_khkk,I_muy,I_pt,Iox; void tinh_tro_khang_roto(){ float rv,rtd,h1r,lamda_rr,epxilonr,phiBr,b1r,delta_Zr, lamda_tr, lamda_dr,lamda_tongr; rv=0.0435*pi*Dv*0.001/(Zr*av*bv); rtd=0.000435*l/Sr; Rr=4*Wsa*Wsa*kda*kda*(rtd+rv/(2*pow(sin(pi*p/Zr),2)))/(Zr*kdr*kdr); cout<<"\nDien tro roto Rr="<<Rr; h1r=h12r+0.9*d2r; lamda_rr=h1r*pow((1-pi*pow(d1r,2)/(8*Sr)),2)/(3*d1r)+0.66- b4r/(2*d1r)+h4r/b4r; lamda_tr=tr/(11.9*khkk*k_delta_r); lamda_dr=2.9*Dv*log10(4.7*Dv/(2*(0.5*av+bv)))/(Zr*10*l*pow((2*sin(pi*p/Zr)),2)); cout<<"\nCac he so tu tan cua roto:\n lamda_rr="<<lamda_rr<<" lamda_tr=" <<lamda_tr<<" lamda_dr="<<lamda_dr; lamda_tongr=lamda_rr+lamda_tr+lamda_dr; cout<<"\n lamda_tongr"<<lamda_tongr; Xr=Xsa*lamda_tongr*Zs*pow((kda/kdr),2)/(Zr*lamda_tong); cout<<"\nDien khang tan day quan chinh roto:Xr="<<Xr; F_khkk=1.6*k_delta*Bkk*khkk*1e+3;//Suc tu dong khe ho khong khi cout<<"\n F_khkk="<<F_khkk; Fm=F_khkk+Fs+Fr;//Tong suc tu dong toan mach I_muy=Fm*p/(0.9*2*Wsa*kda); I_pt=I_muy*100/Idm; Xma=ke*Udm/I_muy;//Dien khang ung voi tu thong khe ho khong khi cout<<"\n Fm="<<Fm<<" I_muy"<<I_muy; cout<<"\n I_pt="<<I_pt; cout<<"\n Xma="<<Xma; getch();} void main(){ clrscr(); nhap(); ktcoban();tustato (); tinh_tro_khang_stato(); turoto(); tinh_tro_khang_roto() getch();} 7)TÝnh tæn hao s¾t #include #include #include #include #include #include #include #include #include #include #include #include float Ptgss,Ptgrr,Ptzrr,Ptss,Ptrr,Ptzss; void tton_hao_sat(){ float Ggs, p1050=2.6, Ggr, Gzs, Gzr, kgc=0.9; Ggs=7.8*3.14*(Dn-hgs)*hgs*l*kc*1e-5; cout<<"\ntrong luong gong stato:Ggs="<<Ggs<<" KG"; cout<<"\nton hao tinh toan phan gong stato: Ptgss="; Ptgss=1.6*p1050*pow(Bgs,2)*Ggs;cout<<Ptgss<<" W"; Ggr=7.8*3.14*(dt+hgr)*hgr*l*kc*1e-5; cout<<"\n trong luong gong roto:Ggr="<<Ggr<<" KG"; cout<<"\nton hao tinh toan phan gong roto: Ptgrr="; Ptgrr=1.6*p1050*pow(Bgr,2)*Ggr; cout<<Ptgrr<<" W"; Gzs=7.8*Zs*bzs*hzs*l*kc*1e-5; cout<<"\ntrong luong rang stato:Gzs="<<Gzs<<" KG"; cout<<"\nton hao tinh toan phan rang stato: Ptzss="; Ptzss=1.8*p1050*pow(Bzs,2)*Gzs*kgc;cout<<Ptzss<<" W"; Gzr=7.8*Zr*bzr*hzr*l*kc*1e-5; cout<<"\ntrong luong rang roto:Gzr="<<Gzr<<" KG"; cout<<"\nton hao tinh toan phan rang roto: Ptzrr="; Ptzrr=1.8*p1050*pow(Bzr,2)*Gzr*kgc; cout<<Ptzrr<<" W"; cout<<"\nton hao sat tinh toan stato: Ptss= "; Ptss=Ptgss+Ptzss; cout<<Ptss<<" W"; cout<<"\nton hao sat tinh toan roto : Ptrr= "; Ptrr=Ptgrr+Ptzrr; cout<<Ptrr<<" W"; getch();} void main(){ clrscr(); nhap(); ktcoban(); tustato(); turoto(); tinh_tro_khang_stato(); tinh_tro_khang_roto(); tton_hao_sat(); getch(); } 8>Modul ®Æc tÝnh lµm viÖc #include #include #include #include #include #include void tao_bang(){ clrscr(); gotoxy(1,1); printf("%c",210); for( int i=0;i<77;i++) printf("%c",198); printf("%c",193 ); for(i=0;i<24;i++) { gotoxy(1,i+2); printf("%c",179);gotoxy(7,i+2); printf("%c",179); gotoxy(12,i+2);printf("%c",179);gotoxy(79,i+2);printf("%c",179);} gotoxy(1,25);printf("%c",179); gotoxy(1,5);printf("%c",195); for( i=0;i<77;i++) printf("%c",196); printf("%c",180);gotoxy(7,1);printf("%c",194); gotoxy(12,1); printf("%c",194);gotoxy(7,5);printf("%c",197); gotoxy(12,5); printf("%c",197);gotoxy(12,3); printf("%c",195); for( i=0;i<66;i++) printf("%c",196); printf("%c",180); for(i=4;i<26;i++) for(int j=1;j<9;j++){ gotoxy(13+j*7,i);printf("%c",179);} for( j=1;j<9;j++){ gotoxy(13+j*7,3); printf("%c",194); gotoxy(13+j*7,5); printf("%c",197);} gotoxy(2,2);cout<<"Tham "; gotoxy(2,3);cout<<" so"; gotoxy(8,2);cout<<"Don";gotoxy(8,3);cout<<"vi"; gotoxy(41,2);cout<<"He so truot";} void tinh_momen_max(); //modul tinh gia tri dinh muc typedef float mang [9] ; float Pco,Pf,Pt,Ptth,anpha,beta,mmaxtt, s_so_ke,sdm,cosphidm,hsdm,Mmax,Mdm,smax; sp Udmp,Zsa; void tinh_gt_dinh_muc() { mang Rra11,Rra22,Pt1,Pt2,Pdr,Xra11,Xra22,s,Pdt,Mdt, M,Ptg,Ps,hsuat,cosphi,n1,Pr,Pds,Prr,Is; sp Ia[9],Zra11[9],Zra1[9],Zra2[9],Zra22[9],Zra[9],Za1[9], E1[9],E2[9],Edm1,Edm2,Edm,Za2[9],Ia1[9],s_phuc,Isa[9]; int i; anpha= Rr/(Xma+Xr); cout<<"\n He so ty le anpha="<<anpha; beta=Xma/(Xma+Xr); cout<<" He so ty le beta="<<beta; Pf=0.005*Pdm/hs;Pco=0.05*Pdm cout<<"\n ton hao phu Pf="<<Pf<<"W"; cout<<" cong suat co Pco="<<Pco; getch(); tao_bang(); s[0]=0.005;s[6]=0.125; for(i=1;i<6;i++) s[i]=0.005+0.02*i; gotoxy(13,4);printf(" %0.3f%c",s[0],179); for(i=1;i<9;i++){ gotoxy(14+i*7,4); printf(" %0.2f",s[i]);} gotoxy(8,6);cout<<" Om"; for(i=0;i<9;i++){ Rra11[i]= anpha*beta*Xma*s[i]/(pow(anpha,2)+pow(s[i],2)); Xra11[i]=beta*Xr*(Rr*anpha/Xr+pow(s[i],2))/(pow(anpha,2)+pow(s[i],2)); Rra22[i]=anpha*beta*Xma*(2-s[i])/(pow(anpha,2)+pow((2-s[i]),2)); Xra22[i]=beta*Xr*(Rr*anpha/Xr+pow((2-s[i]),2))/(pow(anpha,2)+pow((2-s[i]),2));} gotoxy(3,6); printf("Za1");Zsa.create(Rsa,Xsa); for(i=0;i<9;i++){ gotoxy(14+i*7,6); Zra11[i].create(Rra11[i],Xra11[i]); Za1[i]=Zsa+Zra11[i]; printf("%0.1f+",Za1[i].p_thuc());} for(i=0;i<9;i++) {gotoxy(14+i*7,7); printf("j%0.1f",Za1[i].p_ao());}gotoxy(3,8); printf("Za2");gotoxy(8,8);cout<<" Om"; for(i=0;i<9;i++) {gotoxy(14+i*7,8); Zra22[i].create(Rra22[i],Xra22[i]); Za2[i]=Zsa+Zra22[i]; printf("%0.1f+",Za2[i].p_thuc());} for(i=0;i<9;i++){gotoxy(14+i*7,9); printf("j%0.1f",Za2[i].p_ao());}Udmp.create(Udm,0); gotoxy(3,10); printf("Ia");gotoxy(8,10);cout<<" A"; for(i=0;i<9;i++) { gotoxy(14+i*7,10);Ia1[i]=Udmp/(Za2[i]+Za1[i]); Ia[i]=Ia1[i]+Ia1[i]; printf(" %3.2f",Ia[i].h_dung());} gotoxy(3,11);printf("Pdt");gotoxy(8,11);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,11); Pdt[i]=2*pow(Ia[i].h_dung(),2)*(Rra11[i]) - 2*pow(Ia[i].h_dung(),2)* Rra22[i]; printf(" %0.1f",Pdt[i]);} gotoxy(3,12);printf("Mdt");gotoxy(8,12);cout<<"G.cm"; for(i=0;i<9;i++){gotoxy(14+i*7,12); Mdt[i]=97400*p/3000*Pdt[i]; printf("%0.1f",Mdt[i]);}gotoxy(3,13);printf("Prr"); gotoxy(8,13);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,13); Prr[i]=Pdt[i]*(1-s[i]); printf(" %0.1f",Prr[i]);}gotoxy(3,14); printf("Pr");gotoxy(8,14);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,14); Pr[i]=Prr[i]-Pco-Pf; printf(" %0.1f",Pr[i]);} gotoxy(3,15); printf("n"); gotoxy(8,15);cout<<"v/ph"; for(i=0;i<9;i++){ gotoxy(14+i*7,15); n1[i]=3000/p*(1-s[i]); printf(" %0.0f",n1[i]);} gotoxy(3,16); printf("M "); gotoxy(8,16);cout<<"G.cm"; for(i=0;i<9;i++){ gotoxy(14+i*7,16); M[i]=10e+5*Pr[i]/1.028*3000/(1-s[i]); printf("%0.1f",M[i]);}gotoxy(3,17); printf("Pt1"); gotoxy(8,17);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,17); E1[i]=Ia1[i]*Zra11[i]; Pt1[i]=pow((E1[i].h_dung()/(Udm*ke)),2)*Ptss + Ptrr*pow((E1[i].h_dung()/Udm/ke),2)*pow(s[i],1.3); printf(" %0.2f",Pt1[i]);} gotoxy(3,18); printf("Pt2");gotoxy(8,18);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,18); E2[i]=Ia1[i]*Zra22[i]; Pt2[i]=pow((E2[i].h_dung()/Udm/ke),2)*Ptss + Ptrr*pow((E2[i].h_dung()/Udm/ke),2)*pow((2-s[i]),1.3); printf(" %0.2f",Pt2[i]);} gotoxy(3,19);printf("Isa"); gotoxy(8,19);cout<<" A"; for(i=0;i<9;i++){ gotoxy(14+i*7,19); Isa[i].create(Ia[i].p_thuc()+Pt1[i]/E1[i].h_dung() + Pt2[i]/E2[i].h_dung(),Ia[i].p_ao()); printf(" %0.2f",Isa[i].h_dung());} gotoxy(3,20);printf("Pds"); gotoxy(8,20);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,20); Pds[i]=pow((Isa[i].h_dung()),2)*Rsa; printf(" %0.1f",Pds[i]);}gotoxy(3,21); printf("Pdr");gotoxy(8,21);cout<<" W"; for(i=0;i<9;i++){ gotoxy(14+i*7,21); Pdr[i]=2*pow((Isa[i].h_dung()),2)*(Rra11[i]*s[i] +(Rra22[i]*(2-s[i]))); printf(" %0.1f",Pdr[i]);}gotoxy(3,22); printf("Ptg");gotoxy(8,22);cout<<" W"; for(i=0;i<9;i++){gotoxy(14+i*7,22); Ptg[i]=Pt1[i]+Pt2[i]+Pdr[i]+Pds[i]+Pco+Pf; printf(" %0.1f",Ptg[i]);} gotoxy(3,23); printf("Ps");gotoxy(8,23);cout<<" W"; for(i=0;i<9;i++){ gotoxy(14+i*7,23); Ps[i]=Prr[i]+Pdr[i]+Pds[i]+Pt1[i]+Pt2[i]; printf(" %0.1f",Ps[i]);} gotoxy(2,24);printf("hsuat"); for(i=0;i<9;i++){gotoxy(14+i*7,24); hsuat[i]=Pr[i]/Ps[i]; printf(" %0.2f",hsuat[i]);}gotoxy(2,25);printf("c.phi"); for(i=0;i<9;i++){gotoxy(14+i*7,25); cosphi[i]=Isa[i].p_thuc()/Isa[i].h_dung(); printf(" %0.2f",cosphi[i]);} getch(); //tinh sdm,cosdm,hsdm,Mmax int li; for(i=0;i<8;i++){li=i;if(Pdm<Pr[i])break;} sdm=s[li-1]+(s[li]-s[li-1])*(Pdm-Pr[li-1])/(Pr[li]-Pr[li-1]); cout<<"\nsdm="<<sdm; cosphidm=cosphi[li-1]+(cosphi[li]-cosphi[li-1])*(sdm-s[li-1])/(s[li]-s[li-1]); printf(" Cosphidm=%0.3f",cosphidm); hsdm=hsuat[li-1]+(hsuat[li]-hsuat[li-1])*(sdm-s[li-1])/(s[li]-s[li-1]); printf(" hsdm=%0.3f",hsdm); //tinh Mmax Mdm=M[li-1]+(M[li]-M[li-1])*(sdm-s[li-1])/(s[li]-s[li-1]); cout<<" Mdm="<<Mdm; tinh_momen_max(); s_phuc.create((sdm-s[li-1])/(s[li]-s[li-1]),0); Edm1=E1[li-1]+(E1[li]-E1[li-1])*s_phuc; Edm2=E2[li-1]+(E2[li]-E2[li-1])*s_phuc; Edm=Edm1+Edm2; kett=Edm.h_dung()/Udm; printf("\n he so dien ap da chon ke=%0.4f va thuc te kett=%0.4f",ke,kett); s_so_ke=fabs(kett-ke)*100/ke;cout<<"\nSai so ="<<s_so_ke; getch()} // Modul tinh momen max va cac gia tri cua duong dac tinh typedef double mang1 [22] ; sp Isa[22];int csP,imax; mang1 Pr,Pdt,hsuat,cosphiv,M,Is,n1,s; void tinh_momen_max(){ mang1 Rra11,Rra22,Xra11,Xra22,Prr,Pt1,Pt2,Pds,Pdr,Ptg,Ps,Mdt; sp Ia[22],Zra11[22],Zra1[22],Zra2[22],Zra22[22],Zra[22],Za1[22], Za2[22],Ia1[22],E1[22],E2[22]; int i; s[0]=0.005;s[1]=0.025; for(i=2;i<22;i++)s[i]=s[i-1]+0.02; for(i=0;i<22;i++){ Rra11[i]= anpha*beta*Xma*s[i]/(pow(anpha,2)+pow(s[i],2)); Xra11[i]=beta*Xr*(Rr*anpha/Xr+pow(s[i],2))/(pow(anpha,2)+pow(s[i],2)); Rra22[i]=anpha*beta*Xma*(2-s[i])/(pow(anpha,2)+pow((2-s[i]),2)); Xra22[i]=beta*Xr*(Rr*anpha/Xr+pow((2- s[i]),2))/(pow(anpha,2)+pow((2-s[i]),2)); Zra11[i].create(Rra11[i],Xra11[i]); Za1[i]=Zsa+Zra11[i]; Zra22[i].create(Rra22[i],Xra22[i]);Za2[i]=Zsa+Zra22[i]; Ia1[i]=Udmp/(Za2[i]+Za1[i]);Ia[i]=Ia1[i]+Ia1[i]; Pdt[i]=2*pow(Ia[i].h_dung(),2)*(Rra11[i]-Rra22[i]); Prr[i]=Pdt[i]*(1-s[i]); Mdt[i]=97400*p/3000*Pdt[i]; Pr[i]=Prr[i]-Pco-Pf; n1[i]=3000/p*(1-s[i]); M[i]=10e+5*Pr[i]/1.028*3000/(1-s[i]); E1[i]=Ia1[i]*Zra11[i]; Pt1[i]=pow((E1[i].h_dung()/(Udm*ke)),2)*Ptss + Ptrr*pow((E1[i].h_dung()/Udm/ke),2)*pow(s[i],1.3); E2[i]=Ia1[i]*Zra22[i]; Pt2[i]=pow((E2[i].h_dung()/Udm/ke),2)*Ptss+ Ptrr*pow((E2[i].h_dung()/Udm/ke),2)*pow((2-s[i]),1.3); Isa[i].create(Ia[i].p_thuc()+Pt1[i]/E1[i].h_dung()+Pt2[i]/E2[i].h_dung(),Ia[i].p_ao()); Pds[i]=pow((Isa[i].h_dung()),2)*Rsa; Pdr[i]=2*pow((Isa[i].h_dung()),2)*(Rra11[i]*s[i])+(Rra22[i]*(2-s[i])); Ptg[i]=Pt1[i]+Pt2[i]+Pdr[i]+Pds[i]+Pco+Pf; Ps[i]=Prr[i]+Pdr[i]+Pds[i]+Pt1[i]+Pt2[i]; hsuat[i]=Pr[i]/Ps[i]; cosphiv[i]=Isa[i].p_thuc()/Isa[i].h_dung();} float Ptg1; for(i=0;i<22;i++){Ptg1=Pdm+30-Pr[i]; csP=i;if(Ptg1<0) break;} Mmax=M[0];//tinh Mmax for(i=0;i<22;i++)if(Mmax<=M[i]){Mmax=M[i];imax=i; smax=s[i];} cout<<"\nMmax="<<Mmax<<" smax="<<smax;mmaxtt=Mmax/Mdm; printf(" mmaxtt= Mmax/Mdm=%0.3f imax=",mmaxtt,imax);} void Khoi_tao_do_hoa(){ int mh=0,mode=0,i,n; initgraph(&mh,&mode,"c:\\tc\\bgi"); if( graphresult()!=0) exit(1);} void ve_dac_tinh_dm(){ Khoi_tao_do_hoa(); setbkcolor(7);setcolor(9); outtextxy(35,470,"Dac tinh lam viec cua dong co kdb1pha dien dung"); line(30,460,30,20);outtextxy(36,12,"Is(A)"); line(17,460,17,20);outtextxy(17,10,"cosphi");outtextxy(15,22,"hsuat"); line(7,460,7,20); outtextxy(7,12,"n"); line(30,460,620,460);//outtextxy(31,30,"3"); outtextxy(19,463,"O"); outtextxy(620,470,"Pr(W)"); int a[]={620,455,620,465,625,460},b[]={26,20,34,20,30,16}, c[]={2,20,12,20,6,16},d[]={12,20,22,20,17,16}; fillpoly(3,b);fillpoly(3,a); fillpoly(3,c);fillpoly(3,d); mang1 x,y,z,t,k; for(int i=0;i<csP;i++){ x[i]=Pr[i]*590/(Pdm+22)+29;x[i]=(int)x[i]; y[i]=459-440*Isa[i].h_dung()/Isa[csP].h_dung();y[i]=(int)y[i]; z[i]=459-440*cosphiv[i];z[i]=(int)z[i]; t[i]=459-440*hsuat[i];t[i]=(int)t[i]; k[i]=469-440*n1[i]/(n1[0]);k[i]=(int)k[i];} outtextxy(x[csP-2]-3,y[csP-2]-3,"Isa"); moveto(30,y [0]+1); for(i=0;i<csP;i++) {putpixel(x[i],y[i],4);lineto(x[i],y[i]);} outtextxy(x[csP-2]-3,z[csP-2]-3,"cosphi"); moveto(30,z [0]+20); for(i=0;i<csP;i++) {lineto(x[i],z[i]);} outtextxy(x[csP-2]-3,t[csP-2]-3,"hsuat"); moveto(30,460); for(i=0;i<csP;i++) {lineto(x[i],t[i]);} outtextxy(x[csP-2]-3,k[csP-2]-3,"n"); moveto(30,k[0]); for(i=0;i<csP;i++) {lineto(x[i],k[i]);} getch(); closegraph();} void main(void){ clrscr(); nhap(); ktcoban(); tustato(); tinh_tro_khang_stato(); turoto(); tinh_tro_khang_roto(); tton_hao_sat(); tinh_dt_lam_viec(); ve_dac_tinh_dm();} 9>Modul d©y quÊn phô vµ ®Æc tÝnh khëi déng float iktt,mktt,kdb,k=0.744 ,t=0.75,Mkt,Xcv; void tinh_pha_phu(){ float tg1,tg2,Urb,Lsb,Ssb,db,dbcd,Rak,Xak, Rbk,Xbkk,Ik,Iak,Rbkk,Rsbb,Ssbb; float Rsb,Xbk,Mk,A,cosphiak,Ibk,cosphibk,Jbk,Isk,Jak,kldb,Cv, Rrakk,Xrakk,Wsb; sp Zbkkp,Ibkp,Zbkp,Ubp,Ucp,Zc; nen(); cout<<"\n ty so bien ap k=0.744"; cout<<"\n He so day quan phu kdb="<<kdb; Rrakk=anpha*beta*Xma/(pow(anpha,2)+1); Xrakk=beta*Xr*(Rr*anpha/Xr+1)/(pow(anpha,2)+1); cout<<"\n Rrakk="<<Rrakk<<" Xrakk="<<Xrakk; Rak=Rsa+Rrakk; Xak=Xsa+Xrakk; cout<<"\n Vi dong co dien dung nen Qa=Qb nen a=1"; cout<<"\n Rak="<<Rak<<" Xak="<<Xak; Wsb=k*Wsa*kda/kdb;Urb=Wsb/p*Qb; tg1=fabs(Urb-floor(Urb)); tg2=fabs(Urb-ceil(Urb)); //lam tron Urb if(tg1>=tg2) Urb=ceil(Urb); else Urb=floor(Urb);Wsb=Urb*Qb; cout<<"\n So vong day quan pha B Wsb="<<Wsb; kdb=k*Wsa*kda/Wsb; Rbk=k*k*Rakk + Rsb cout<<"\n Rsa="<<Rsa; Rbkk=Rbk; cout<<" Dtro tac dung day phu :Rbk=Rbkk"<<Rbkk; Rsbb=Rbk-k*t*Rrakk; cout<<"\n Rbkk="<<Rbkk<<" Rrakk"<<Rrakk; Ssbb=Ssa/t; cout<<"\n Tiet dien dq phu chua qui chuan:Ssbb="<<Ssbb; Ssb=tra_tiet_dien(Ssbb); cout<<" sau khi qui chuan:Ssb="<<Ssb; db=Tra_dkocd(Ssbb); cout<<"\n Duong kinh day tran:db="<<db; dbcd=Tra_dk_cd(Ssbb); cout<<" duong kinh day co cach dien:dbcd="<<dbcd; kldb=(Urb*dbcd*dbcd)/(0.9*Srs); cout<<"\n He so lap day:"<<kldb; Rsb=Rsbb*Ssbb/Ssb; cout<<"\n Dien tro thuc dq phu:Rsb="<<Rsb; Rbk=Rsb+k*t*Rrakk; cout<<"\n Dien tro :Rbk="<<Rbk;Xbk=k*kXakk - Xcv cout<<"\n :Xbk="<<Xbk; Mk=mk*Mdm/1000; cout<<"\n Mdm="<<Mdm<<"G.cm mk="<<mk; cout<<" momen khoi dong Mk="<<Mk<<"Kg.cm"; cout<<" Xbkk="<<Xbkk; Xcv=fabs(k*k*Xa1 +k*Ra1) cout<<"\n Dung khang cua tu khoi dong Xcv="<<Xcv; Cv=1e+6/(100*pi*Xcv); cout<<"\n Dien dung tu dien Cv="<<Cv<<"(micro fara)";Cv=ceil(Cv); cout<<" Lam tron :Cv="<<Cv; Xcv=1e+6/(100*pi*Cv); cout<<"\n Dung khang thuc:Xcv="<<Xcv; cout<<" Xbkk="<<Xbkk; Iak1=(Udm/2)/ ((1/Zak.create(Rak,Xak) - (k.create(0,1)/Zbk.create(Rbk,Xbk))) Iak2=(Udm/2)/ ((1/Zak.create(Rak,Xak) + (k.create(0,1)/Zbk.create(Rbk,Xbk))) cout<<"\n Rak= "<<Rak<<" Xak="<<Xak; cout<<"\n Iak=Iak1+Iak2 "<<Iak;getch(); Ibk=create(0,1).((Iak1- Iak2)/k) cout<<"\n Dong dien pha phu luc khoi dong:Ibk="<<Ibk<<"A"; cosphibk=Rbkk/sqrt(Rbkk*Rbkk+Xbkk*Xbkk); cout<<"\n He so cong suat pha phu:cosphibk="<<cosphibk; Ik=Iak +Ibk cout<<" dong dien khoi dong:Ik="<<Ik<<"A"; iktt=Ik/Idm; Jbk=Ibk/Ssb; cout<<"\n Mat do dong day quan phu:Jbk="<<Jbk<<"A/mm2"; Jak=Iak/Ssa; cout<<"\n Mat do dong day quan chinh:Jak="<<Jak<<"A/mm2"; cout<<"\n Rbkk="<<Rbkk<<" Xak="<<Xak<<" Xbkk="<<Xbkk<<" Rak="<<Rak<<" A="<<A; Pdtk=2*Rakk*(Iak1*Iak1+Iak2*Iak2) Mkt=Pdtk*10e+5/1.028*3000 cout<<"\n Momen khoi dong :Mkt="<<Mkt<<"kG.cm"; mktt=Mkt*1000/Mdm; cout<<"\n boi so mo mem khoidong mktt="<<mktt; Zbkkp.create(Rbkk,Xbkk); cout<<"\n Zbkkp=";Zbkkp.hth(Zbkkp);Ibkp=Udmp/Zbkkp; cout<<" Ibkp=";Ibkp.hth(Ibkp);Zbkp.create(Rbkk,Xbk); cout<<"\n Zbkp=";Zbkp.hth(Zbkp);Ubp=Ibkp*Zbkp; cout<<"\n Dien ap dq phu luc mo may:Ubp=";Ubp.hth(Ubp); Zc.create(0,-Xcv); cout<<"\n Zc=";Zc.hth(Zc);Ucp=Ibkp*Zc; cout<<" dien ap tren tu:Ucp=";Ucp.hth(Ucp); getch();} void in_ket_qua(){ clrscr(); textmode(C80); textbackground(1); window(1,1,80,25); clrscr(); textcolor(12); gotoxy(10,2); cprintf("KET QUA TINH TOAN DONG CO KHONG DONG BO MOT PHA DIEN DUNG"); textbackground(7); window(3,3,77,24); clrscr(); cprintf("\nI)Kich thuoc stato"); gotoxy(5,3); cprintf("Dn=%6.2f D=%5.3f l=%5.3f Zs=%4.0f bzs=%5.3f hzs=%5.3f hgs=%5.3f",Dn,D,l,Zs,bzs,hzs,hgs); gotoxy(5,4); cprintf("d1s=%5.2f d2s=%5.2f ",d1s,d2s); getch();} void main(){ clrscr(); nhap(); ktcoban(); tustato(); tinh_tro_khang_stato(); turoto(); tinh_tro_khang_roto(); tton_hao_sat(); tinh_dt_lam_viec(); tinh_pha_phu(); getch();} 10>TÝnh to¸n chÕ ®é khëi ®éng #include #include #include #include void tao_bang_kd(){ clrscr(); gotoxy(30,1); cout<<"Bang tinh toan dac tinh khoi dong"; gotoxy(1,2); printf("%c",218); for( int i=0;i<77;i++) printf("%c",196); printf("%c",191 ); for(i=0;i<23;i++){gotoxy(1,i+3); printf("%c",179);gotoxy(7,i+3);printf("%c",179); gotoxy(12,i+3); printf("%c",179); gotoxy(79,i+3); printf("%c",179);}gotoxy(1,6); printf("%c",195); for( i=0;i<77;i++) printf("%c",196); printf("%c",180); gotoxy(7,2); printf("%c",194); gotoxy(12,2); printf("%c",194); gotoxy(7,6);printf("%c",197); gotoxy(12,6); printf("%c",197); gotoxy(12,4);printf("%c",195); for( i=0;i<66;i++) printf("%c",196); for(i=4;i<25;i++) for(int j=1;j<6;j++){ gotoxy(13+j*11,i+1);printf("%c",179);} gotoxy(1,25); printf("%c",192 ); for( j=0;j<77;j++)printf("%c",196); printf("%c",217 );for( j=1;j<6;j++){ gotoxy(13+j*11,4);printf("%c",194); gotoxy(13+j*11,6); printf("%c",197); gotoxy(13+j*11,25);printf("%c",193);} gotoxy(2,3);cout<<"Tham "; gotoxy(2,4);cout<<" so"; gotoxy(8,3);cout<<"Don";gotoxy(8,4);cout<<"vi"; gotoxy(41,3);cout<<"He so truot s"; gotoxy(3,7); printf("Ra11");gotoxy(3,8); printf("Xa11"); gotoxy(3,9); printf("Ra22");gotoxy(3,10); printf("Xa22"); gotoxy(3,11);printf("Za1");gotoxy(3,12); printf("Za2"); gotoxy(3,13); printf("Zb1");gotoxy(3,14); printf("Zb2"); gotoxy(3,15); printf("Ia1");gotoxy(3,16); printf("Ia2"); gotoxy(3,17);printf("Ia");gotoxy(3,18); printf("Ib"); gotoxy(3,19);printf("I");gotoxy(3,20); printf("Pdt"); gotoxy(3,21); printf("Mdt");gotoxy(3,22); printf("Pr"); gotoxy(3,23); printf("n");gotoxy(3,24); printf("M"); for( j=0;j<8;j++){gotoxy(8,7+j);cout<<" Om";} for( j=0;j<5;j++){gotoxy(8,15+j);cout<<" A";} gotoxy(8,20);cout<<" W";gotoxy(8,21);cout<<"G.cm"; gotoxy(8,22);cout<<" W"; gotoxy(8,23);cout<<"v/ph"; gotoxy(8,24);cout<<"G.cm";gotoxy(7,25);printf("%c",193); gotoxy(12,25);printf("%c",193);} typedef float mang2 [6] ; mang2 Mkd,s1; void tinh_dac_tinh_kd(){ mang2 Rra11,Rra22,Xra11,Xra22,Pdt,Mdt, Pr,Pds,Prr,Is,n2; sp I[6],Ia[6],Ib[6],Zra11[6],Zra1[6],Zra2[6],Zra22[6],Zra[6],Za1[6], k_phuc,Za2[6],Ia1[6],Ia2[6],k1_phuc,Isa[6],Zb1[6],Zb2[6]; int i; tao_bang_kd(); for(i=0;i<6;i++) {s1[i]=smax+i*(1-smax)/5; gotoxy(15+i*11,5); printf(" %0.3f",s1[i]);} for(i=0;i<6;i++){ Rra11[i]= anpha*beta*Xma*s1[i]/(pow(anpha,2)+pow(s1[i],2)); gotoxy(15+i*11,7); printf("%0.4f",Rra11[i]); Xra11[i]=beta*Xr*(Rr*anpha/Xr+pow(s1[i],2))/(pow(anpha,2) +pow(s1[i],2)); gotoxy(15+i*11,8);printf("%0.4f",Xra11[i]); Rra22[i]=anpha*beta*Xma*(2-s1[i])/(pow(anpha,2)+pow((2-s1[i]),2)); gotoxy(15+i*11,9); printf("%0.4f",Rra22[i]); Xra22[i]=beta*Xr*(Rr*anpha/Xr +pow((2- s1[i]),2))/(pow(anpha,2)+pow((2-s1[i]),2)); gotoxy(15+i*11,10);printf("%0.4f",Xra22[i]);} k_phuc.create(0,k); k1_phuc.create(0,(1/k)); for(i=0;i<6;i++){gotoxy(14+i*11,11); Zra11[i].create(Rra11[i],Xra11[i]); Za1[i]=Zsa+Zra11[i]; Zb1[i]. create((k*t*a*pow((kda/kdb),2)*Rsa + k*k*Rra11[i]),(k*t*pow((kda/kdb),2)*Xsa+k*k*Xra11[i]-Xcv)); Zb2[i].create((k*t*a*pow((kda/kdb),2)*Rsa + k*k*Rra22[i]),(k*t*a*pow((kda/kdb),2)*Xsa+k*k*Xra22[i]-Xcv)); printf("%0.0f+j%0.1f",Za1[i].p_thuc(),Za1[i].p_ao());gotoxy(14+i*11,13); printf("%0.0f - j%0.1f",Zb1[i].p_thuc(),fabs(Zb1[i].p_ao())); gotoxy(14+i*11,14); printf("%0.0f-j%0.1f",Zb2[i].p_thuc(),fabs(Zb2[i].p_ao()));} for(i=0;i<6;i++){ gotoxy(14+i*11,12); Zra22[i].create(Rra22[i],Xra22[i]); Za2[i]=Zsa+Zra22[i]; printf("%0.0f+j%0.1f",Za2[i].p_thuc(),Za2[i].p_ao());} for(i=0;i<6;i++){ gotoxy(15+i*11,15); Ia1[i]=Udmp*(Zb2[i]+k_phuc*Za2[i])/(Zb1[i]*Za2[i]+Za1[i]*Zb2[i]); Ia2[i]=Udmp*(Zb1[i]+k_phuc*Za1[i])/(Zb1[i]*Za2[i]+Za1[i]*Zb2[i]); Ia[i]=Ia1[i]+Ia2[i]; Ib[i]=(Ia1[i]+Ia2[i])*k1_phuc; I[i]=Ia[i]+Ib[i]; printf("%0.3f",Ia1[i].h_dung()); gotoxy(15+i*11,16); printf("%0.3f",Ia2[i].h_dung());gotoxy(15+i*11,17); printf("%0.3f",Ia[i].h_dung());gotoxy(15+i*11,18); printf("%0.3f",Ib[i].h_dung());gotoxy(15+i*11,19); printf("%0.3f",I[i].h_dung());} for(i=0;i<6;i++) { gotoxy(15+i*11,20); Pdt[i]=2*(pow(Ia1[i].h_dung(),2)*Rra11[i] - pow(Ia2[i].h_dung(),2)*Rra22[i]); printf(" %0.2f",Pdt[i]);}for(i=0;i<6;i++){ gotoxy(15+i*11,21); Mdt[i]=97400*p/3000*Pdt[i]; printf("%0.2f",Mdt[i]);} for(i=0;i<5;i++){gotoxy(15+i*11,22); Prr[i]=Pdt[i]*(1-s1[i]); Pr[i]=Prr[i]-Pco-Pf; printf(" %0.2f",Pr[i]); } for(i=0;i<5;i++){ gotoxy(15+i*11,23); n2[i]=3000/p*(1-s1[i]); printf(" %0.0f",n2[i]);}for(i=0;i<5;i++){ Mkd[i]=97400*Pr[i]*p/3000/(1-s1[i]);} Mkd[5]=Mkt*1000;for(i=0;i<6;i++){ gotoxy(15+i*11,24);printf("%0.1f",Mkd[i]); } getch();} void ve_dac_tinh_momen(){ Khoi_tao_do_hoa(); setbkcolor(7); setcolor(9); outtextxy(36,12,"M"); line(30,460,30,20);outtextxy(35,470,"Dac tinh M=f(s) cua dong co kdb 1 pha dien dung "); line(30,460,620,460); outtextxy(610,470,"1"); outtextxy(19,463,"O"); outtextxy(620,470,"s"); int a[]={620,455,620,465,625,460},b[]={26,20,34,20,30,16}; fillpoly(3,b);fillpoly(3,a); mang1 x,y; for(int i=0;i<22;i++){ x[i]=s[i]*590+29;x[i]=(int)x[i]; y[i]=459-380*M[i]/Mmax;y[i]=(int)y[i];} moveto(30,460); for(i=0;i<=imax;i++) lineto(x[i],y[i]); setlinestyle(3,0,1); for(i=imax;i<22;i++) lineto(x[i],y[i]); lineto(610,460); mang2 x1,y1;//ve doan dac tinh khoi dong setlinestyle(0,0,1); for( i=0;i<6;i++) { x1[i]=s1[i]*590+29;x1[i]=(int)x1[i]; y1[i]=439-380*Mkd[i]/Mmax;y1[i]=(int)y1[i];} moveto(x[imax-1],y[imax-1]); for(i=0;i<6;i++) lineto(x1[i],y1[i]);lineto(610,440); getch();closegraph();} void main(){ clrscr(); nhap(); ktcoban(); tustato(); tinh_tro_khang_stato(); turoto(); tinh_tro_khang_roto(); tton_hao_sat(); tinh_dt_lam_viec(); ve_dac_tinh_lv(); tinh_pha_phu(); tinh_dac_tinh_kd(); ve_dac_tinh_momen(); in_ket_qua() } 11.Ch­¬ng tr×nh chÝnh #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include void tinh_tro_khang_roto(); void tao_do_hoa(); void tinh_tro_khang_stato(); float p_an; float bt1,lda,Kd,Bkk,Att,khkk,kett,Zs,Zr,Dn,D,l,Wsa,Ura,Ssa,d,dcd; void tustato(); void Phuong_an_truoc(){ cout<<"\n Phuong an truoc ban da chon cac thong so nhu sau:"; printf("\nbeta1=%0.2f lamda=%0.2f Kd=%0.2f Bkk=%0.2f A=%0.2f khkk=%0.2f ke=%0.2f Zs=%0.2f Zr=%0.2f", bt1,lda,Kd,Bkk,Att,khkk,kett,Zs,Zr); cout<<"\n Ket qua tinh toan:"; printf("\n Dn=%0.2f D=%0.2f l=%0.2f Wsa=%0.0f Ura=%0.0f Ssa=%0.4f d=%0.3f dcd=%0.3f", Dn,D,l,Wsa,Ura,Ssa,d,dcd);} void main(){ clrscr(); tao_do_hoa(); getch(); nhap();do{ Nhan: ktcoban(); tustato(); tinh_tro_khang_stato(); turoto(); tinh_tro_khang_roto(); tton_hao_sat(); tinh_gt_dinh_muc(); if(s_so_ke>5){ cout<<"\n Sai so ke la qua lon phai chon lai ke=(ke+kett)/2=%0.2f"<<(ke+kett)/2; continue;} if(mmaxtt<mmax){ cout<<"\n Boi so momem max khong dat can tang chieu dai l de giam Wsa"; Phuong_an_truoc(); continue;} if(cosphidm<cosphi){ cout<<"\n Cosphi khong dat nen quay lai de giam mat do tu thong khe ho khong khi Bkk"; Phuong_an_truoc(); continue;} if(hsdm<hs){ cout<<"\n Hieu suat khong dat nen ban hay chon phuong phap de tang hieu suat "; printf("\n I)Tang tiet dien day dan neu Kld con be chon cach nay ban hay go 1 Kld=",Kld); printf("\n II)Giam mat do tu thong khkk Bkk va tang chieu dai stato ,go2"); cout>p_an; Phuong_an_truoc();}} while(hsdm<hs); ve_dac_tinh_dm(); tinh_pha_phu(); tinh_dac_tinh_kd(); ve_dac_tinh_momen(); //in_ket_qua(); getch(); } void tao_do_hoa(){ int mh=0,mode=0; initgraph(&mh,&mode,); setbkcolor(BLUE); setcolor(RED); settextstyle(0,0,1); outtextxy(160,20," TRUONG DAI HOC BACH KHOA HA NOI"); outtextxy(160,40," KHOA DIEN"); outtextxy(160,60," BO MON THIET BI DIEN -DIEN TU"); outtextxy(160,80," *********"); settextstyle(0,0,2); outtextxy(10,160," CHUONG TRINH THIET KE DONG CO "); outtextxy(0,200," KHONG DONG BO MOT PHA DIEN DUNG"); settextstyle(0,0,1); outtextxy(160,300," GVHD:TS NGUYEN HONG THANH"); outtextxy(160,320," SVTH:NGUYEN HUU XUYEN");} KÕt luËn Qua qu¸ tr×nh tÝnh to¸n em nhËn thÊy r»ng c¸c kÕt qu¶ ®¹t ®­îc ®Òu phï hîp víi yªu cÇu thiÕt kÕ. ViÖc tèi ­u ho¸ m¹ch tõ stato vµ roto ®· n©ng cao hÖ sè c«ng suÊt cosj, gi¶m dßng ®iÖn tõ ho¸. §éng c¬ cã tô lµm viÖc cã ®Æc tÝnh lµm viÖc t­¬ng ®èi tèt: h=(0,5--- 0,9); hÖ sè c«ng suÊt cosj =(0,8--- 0,95); Mmax=(1,6---2,2)M®m.Nh­îc ®iÓm cña ®éng c¬ nµy lµ m« men khëi ®éng nhá:Mk=(0,3--- 0,6)M®m.§ã lµ do khi khëi ®éng, thµnh phÇn m«men thø tù nghÞch M2 lín v× tõ tr­êng kh«ng trßn. §Ó t¨ng m«men khëi ®éng cña ®éng c¬ khi cÇn thiÕt cã thÓ t¨ng ®iÖn trë cña roto hoÆc ®iÖn dung cu¶ tô ®iÖn, hoÆc chän c¸c th«ng sè cña ®éng c¬ ®Ó ®¶m b¶o tõ tr­êng trßn kh«ng ph¶i ë hÖ sè ®Þnh møc mµ ë hÖ sè tr­ît lín h¬n. Tuy nhiªn víi c¸c biÖn ph¸p t¨ng m«men khëi ®éng trªn, hiÖu suÊt ë chÕ ®é ®Þnh møc gi¶m. Qua qu¸ tr×nh thiÕt kÕ b»ng m¸y tÝnh em nhËn thÊy r»ng: ¦u ®iÓm thêi gian tÝnh to¸n ng¾n, ®é chÝnh x¸c cao, ®Æc biÖt cã thÓ thay ®æi ph­¬ng ¸n thiÕt kÕ rÔ rµng,nªn dÔ lùa chän ®­îc ph­¬ng ¸n tèi ­u. Nh­îc ®iÓm lµ c¬ së d÷ liÖu qu¸ phong phó,nhiÒu tªn biÕn nªn viÖc lËp tr×nh gÆp mét sè khã kh¨n nhÊt ®Þnh. V× thêi gian vµ tr×nh ®é cã h¹n nªn trong quyÓn ®å ¸n nµy cßn mét sè thiÕu sãt ,rÊt mong c¸c thÊy,c« gi¸o chØ b¶o vµ bæ xung ®Ó quyÓn ®å ¸n cña em ®­îc hoµn thiÖn h¬n. Em xin ch©n thµnh c¶m ¬n. PhÇn iii Chuyªn ®Ò m«men phô 1.Kh¸i niÖm Khi ph©n tÝch ®Æc tÝnh m«men ta chØ xÕt ®Õn t¸c dông cña tõ tr­êng sãng c¬ b¶n. Nh­ng suÊt tõ ®éng vµ tõ c¶m kh«ng hoµn toµn ph©n bè theo h×nh sin, nghÜa lµ suÊt tõ ®éng cña d©y quÊn stato vµ roto ngoµi sãng c¬ b¶n cßn cã sãng bËc cao, trong ®ã bao gåm sãng ®iÒu hoµ r¨ng. Nh÷ng tõ tr­êng sãng bËc cao ®ã quay víi tèc ®é kh¸c nhau vµ cïng sinh ra m«men. Nh÷ng m«men ®ã gäi lµ m«men phô cña m¸y ®iÖn, nh÷ng m«men nµy rÊt yÕu so víi m«men do sãng c¬ b¶n cña tõ tr­êng sinh ra. Nh­ng trong tr­êng hîp nhÊt ®Þnh nh­ ë tèc ®é thÊp nã cã thÓ sinh ra m«men h·m t­¬ng ®èi lín ¶nh h­ëng ®Õn sù lµm viÖc cña m¸y ®iÖn ®Æc biÖt lµ trong qu¸ tr×nh më m¸y. 2.C¸c lo¹i m«men phô *M«men phô kh«ng ®ång bé §Æc tÝnh M=f(S) khi xÐt ®Õn sãng ®iÒu hoµ bËc cao Dï tèc ®é cña stato vµ roto quay nh­ thÕ nµo th× suÊt tõ ®éng cña sãng c¬ b¶n cña stato vµ roto ®Òu quay trong kh«ng gian víi tèc ®é ®ång bé. Do ®ã sinh ra m«men ®iÖn tõ vµ cã ®Æc tÝnh m«men M=f(S). c¸c sãng ®iÒu hoµ cña suÊt tõ ®éng stato cã tèc ®é quay kh¸c nhau vµ c¶m øng trªn roto nh÷ng suÊt tõ ®éng quay cã cïng tèc ®é vµ sè ®«i cùc, do ®ã cïng sinh ra m«men.Nh÷ng sãng bËc n=6k+1 quay thuËn vµ sãng bËc n=6k-1 quay nghÞch (víi k lµ mét sè nguyen bÊt kú), vµ tèc ®é quay cña tõ tr­êng sãng bËc g lµ: nv=±.n1 Trong ®éng c¬ c«ng suÊt nhá th× tån t¹i nhiÒu thµnh phÇn sãng bËc 3, c¸c sãng bÊc cao nh­ bÊc 5 vµ 7 còng rÊt quan träng v× biªn ®é cña nã t­¬ng ®èi lín vµ m«men phô sinh ra ¶nh h­ëng nhiÒu ®Õn m«men cña m¸y ®iÖn. Trong m¸y ®iÖn ngoµi thµnh phÇn sãng bËc 5 vµ 7 th× c¸c sãng bËc cao kh¸c chØ cã sãng ®iÒu hoµ r¨ng lµ ¶nh h­ëng râ rÖt mµ th«i. - §­êng1: do tõ tr­êng sãng bËc c¬ b¶n sinh ra -§­êng 2: do tõ tr­êng sãng bËc 7 sinh ra -§­êng3: do tõ tr­êng sãng bËc 5 sinh ra -§­êng4: do tõ tr­êng tæng cña sãng bËc 5 vµ 7 sinh ra -T¹i ®iÓm a øng víi Mminth× ®éng c¬ dõng hoÆt ®éng *M«men phô ®ång bé §­îc sinh ra do mét sãng ®iÒu hoµ bËc cao nµo ®ã cña tõ tr­êng roto t¸c dông víi mét sãng ®iÒu hoµ bËc cao cã cïng sè ®«i cùc cña tõ tr­êng roto.NghÜa lµ hai sãng ®iÒu hoµ cïng sè ®«i cùc ®ã cã cïng tèc ®é trong kh«ng gian nh­ nhau míi sinh ra ®­îc m«men. V× sãng ®iÒu hoµ cña roto cã cïng tèc ®é nhÊt ®Þnh nªn roto ph¶i cã mét tèc ®é nhÊt ®Þnh nµo ®ã míi sinh ra m«men ®­îc.M«men phô ®ång bé chñ yÕu sinh ra do suÊt tõ ®éng cña sãng ®iÒu hoµ r¨ng cña stato vµ roto sinh ra do sù phèi hîp gi÷a r·nh stato vµ roto cã quan hÖ nhiÒu ®Õn viÖc sinh ra m«men nµy. §­êng 1 øng víi Z1=24,Z2=20 §­êng 2 øng víi Z1=24,Z2=28 *M«men sinh ra chÊn ®éng vµ t¹p ©m do tõ tr­êng sãng ®iÒu hoµ sinh ra §éng c¬ ®iÖn khi lµm viÖc th­êng kªu vµ rung. Nh÷ng t¹p ©m vµ chÊn ®éng ®ã ngoµi nguyªn nh©n c¬ khÝ ra, trong nhiÒu tr­êng hîp lµ do lùc tõ kÐo lÖch trong khe hë sinh ra. Khi trôc cña r¨ng stato vµ roto trïng nhau th× lùc kÐo ®ã cµng lín. NÕu trªn chu vi khe hë kh«ng cã chç ®èi xøng nµo gièng nh­ vËy th× sinh ra lùc kÐo lÖch mét chiÒu theo h­íng kÝnh. Khi roto quay lùc tõ lÖch ®ã còng quay lµm m¸y rung vµ tÇn sè rung ®ã trïng víi tÇn sè rung tù nhiªn th× sinh ra céng h­ëng nghiªm träng. 3.Ph­¬ng ph¸p trõ khö m«men phô Nguyªn nh©n sinh ra m«men phô lµ do suÊt tõ ®éng sãng ®iÒu hoµ trong ®ã cã suÊt tõ ®éng cña sãng ®iÒu hoµ r¨ng. V× vËy ®Ó trõ khö m«men phô th× ph¶i lµm yÕu suÊt tõ ®éng cña sãng ®iÒu hoµ ®i. *Muèn triÖt tiªu hoµn toµn sãng bËc 3 th× ta cã thÓ dïng d©y quÊn sin . *Muèn lµm yÕu sãng bËc 5 hay bËc 7 th× cã thÓ dïng d©y quÊn b­íc ng¾n. *Muèn lµm yÕu sãng ®iÒu hoµ r¨ng th× th× chän phèi hîp r·nh thÝch ®¸ng. *Ph­¬ng ph¸p cã hiÖu qu¶ n÷a lµ dïng r·nh chÐo ë roto , th­êng lµ chÐo mét b­íc r¨ng.Nã lµm cho suÊt tõ ®éng cña r·nh phèi hîp ®Òu trªn qu·ng chÐo mµ kh«ng tËp trung t¹i mét ®iÓm nªn cã thÓ lµm yÕu ®i sãng ®iÒu hoµ r¨ng cña ®­¬ng ph©n bè suÊt tõ ®éng khe hë tæng.R·nh chÐo th­êng dïng trong ®éng c¬ ®iÖn roto lång sãc c«ng suÊt nhá. *§­êng1: øng víi r·nh kh«ng chÐo. *§­¬ng2: øng víi r·nh chÐo. 4.C¸ch tÝnh m«men phô cña ®éng c¬ kh«ng ®ång bé mét pha Mnk=M1.An Trong ®ã: An = .()2 n: BËc cña sãng ZR: Sè r·nh roto P: sè ®«i cùc kdqn: HÖ sè d©y quÊn cña sãng bËc n Víi n = 1, 3, 5, 7, 11, 13 ;Ta cã b¶ng tÝnh to¸n sau n kdqn An Mnk mk=Mnk/M®m 1 0,9028 1 3027,953 0,497 3 0,3079 0,3242 981,662 0,1611 5 0,1936 0,2498 756,383 0,1242 7 0,1485 0,1197 362,446 0,0595 11 0,1185 0,0543 164,418 0,0270 13 0,1129 0,0311 94,1693 0,0155 PhÇn iv Tµi liÖu tham kh¶o 1.T¸c gi¶ TrÇn Kh¸nh Hµ +§éng c¬ kh«ng ®ång bé mét pha vµ ba pha c«ng suÊt nhá xuÊt b¶n n¨m 1993 +ThiÕt kÕ m¸y ®iÖn xuÊt b¶n n¨m 1998 2.T¸c gi¶ NguyÔn Hång Thanh +M¸y ®iÖn trong ®iÒu khiÓn tù ®éng xuÊt b¶n n¨m 1999 +ThiÕt kÕ m¸y ®iÖn xuÊt b¶n n¨m 1998 3.T¸c gi¶ Phan Tö Thô +M¸y ®iÖn I xuÊt b¶n n¨m 1996 +M¸y ®iÖn II xuÊt b¶n n¨m 1996 4.T¸c gi¶ Ph¹m V¨n Êt +Kü thuËt lËp tr×nh C, c¬ së vµ n©ng cao +Kü thuËt lËp tr×nh C++ xuÊt b¶n n¨m 1999 5.T¸c gi¶ TrÇn TuÊn & Lª V¨n Doanh +101 thuËt to¸n dïng trong kü thuËt ®iÖn xuÊt b¶n n¨m 2000 6.T¸c gi¶ NguyÕn §øc Sü +C«ng nghÖ chÕ t¹o m¸y ®iÖn & m¸y biÕn ¸p xuÊt b¶n n¨m 1995 phÇn v phô lôc mét sè chó ý khi sö dông ®éng c¬ kh«ng ®ång bé mét pha ®iÖn dung 1.Khi l¾p ®Æt *§éng c¬ ph¶i ®­îc l¾p ë vÞ trÝ dÔ kiÓm tra, th¸o l¾p khi cÇn thiÕt, m«i tr­êng tho¸ng m¸t, kh« r¸o, kh«ng bÞ ¶nh h­ëng cña h¬i n­íc vµ ho¸ chÊt. *L¾p ®Æt ®éng c¬ trªn nÒn hoÆc bÖ m¸y kh«ng bÞ nón sau thêi gian sö dông. C¸c bul«ng ch©n ®Õ ph¶i xiÕt chÆt. *§éng c¬ ph¶i ®­îc nèi tiÕp ®Êt qua bul«ng tiÕp ®Þa g¾n trªn ®éng c¬ ®Ó ®¶m b¶o an toµn khi sù cè xÈy ra. *Khi muèn ®¶o chiÒu ®éng c¬ ta chØ cÇn b¾t l¹i cÇu ®ång trªn b¶n cùc.§Ó ®¶m b¶o tuæi thä cña ®éng c¬ th× nguån ®iÖn ®­a vµo ph¶i qua thiÕt bÞ ®ãng ng¾t vµ thiÕt bÞ b¶o vÖ ®éng c¬ khi lµm viÖc. *®Ó thuËn tiÖn cho viÖc kiÓm tra ®iÖn ¸p nguån vµ dßng kh«ng t¶i ta l¾p thªm ®ång hå v«n kÕ vµ ampe kÕ vµo m¹ch ®iÖn ë vÞ trÝ dÔ kiÓm tra nhÊt. 2.khi vËn hµnh *Tr­íc khi ®ãng ®iÖn vËn hµnh ®éng c¬, cÇn kiÓm tra hÖ thèng c¬ xem cã bÞ kÑt kh«ng. *Khi ®éng c¬ lµm viÖc trÞ sè dßng ®iÖn kh«ng ®­îc v­ît qu¸ trÞ sè ghi trªn nh·n. §iÖn ¸p ®éng c¬ khi kÐo t¶i cho phÐp sai sè ±5% so víi ®iÖn ¸p ghi trªn nh·n. Khi®iÖn ¸p l­íi thÊp h¬n ph¹m vi cho phÐp, yªu cÇu ph¶i gi¶m t¶i ®Ó dßng ®iÖn kh«ng v­ît qu¸ dßng ®Þnh møc. *§èi víi ®éng c¬ ®iÖn dung th× kh«ng ®­îc vËn hµnh ë chÕ ®é kh«ng t¶i víi thêi gian lín, v× dßng ®iÖn trong cuén khëi ®éng t¨ng cao lµm ph¸t nãng vµ cã thÓ lµm ch¸y cuén d©y. 3.H­ háng th­êng gÆp *§éng c¬ ch¹y bÞ rung, cã tiÕng kªu, ph¶i kiÓm tra hÖ thèng l¾p ®Æt, c©n chØnh ®é ®ång t©m gi÷a c¸c trôc vµ khíp nèi... *§éng c¬ ch¹y ph¸t nãng nhanh, qu¸ nhiÖt ®é cho phÐp cÇn kiÓm tra l¹i t¶i cã lín kh«ng, ®iÖn ¸p cÊp cho ®éng c¬ cã bÞ gi¶m kh«ng. *Khi ®ãng ®iÖn ®éng c¬ kh«ng quay, rung m¹nh vµ cã tiÕng kªu, måi tay theo chiÒu nµo ®éng c¬ quay theo chiÒu ®ã th× cÇn kiÓm tra l¹i tô vµ xem cuén khëi ®éng cã hë m¹ch kh«ng.